WebJun 14, 2016 · Clojure barely touches this problem space, especially when it comes to nested or recursive data structures. Adding functions to Clojure that are significantly inferior in both semantics and performance to what already exists in an external library seems pretty silly to me. Just my two cents. 0 votes answered Nov 17, 2024 by jira WebApr 15, 2013 · How do I convert a clojure map into string, almost key value pair, as shown below: Clojure data: (def data { :starks "Winter is coming" :Lannisters "Hear me roar" }) I want to convert the above to "starks" "winter is coming" "Lannisters" "hear me roar"
Clojure destruct map to parse as key parameters - Stack Overflow
WebLike most functions in Clojure that work with collections, doseq internally calls seq on your collection before iterating over it. So you can simply do this: user> (doseq [keyval db] (prn keyval)) [:subprotocol "mysql"] [:username "usr"] [:classname "com.mysql.jdbc.Driver"] [:subname "//100.100.100.100:3306/clo"] [:password "pwd"] WebFeb 19, 2012 · In clojure, it is possible to destructure some keys of a map like this: (let [ {:keys [cpp js]} {:cpp 88 :js 90}] (println js); 90 (println cpp); 88 ) Is there a way to destructure all the keys of a map? Maybe something like: (let [ {:all-the-keys} {:cpp 88 :js 90}] (println js); 90 (println cpp); 88 ) clojure Share Improve this question Follow bas javid wikipedia
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WebFeb 23, 2012 · Clojure doc states that (keys map) and (vals map) function results are ordered with the same order as the (seq map) function. Thus, by associativity, they all have the same order. :) @gtrak – Yonathan W'Gebriel Sep 4, 2024 at 23:07 This is the most elegant solution – danfromisrael Mar 27, 2024 at 12:36 Add a comment 1 WebJan 6, 2011 · Clojure provides the get and get-in functions for returning values from a map and the select-keys function for returning a new map of only the specified keys. Clojure … WebMay 27, 2016 · clojure maps keyword optional-parameters nested-map Share Follow asked May 27, 2016 at 22:30 Jonathan 11 2 Add a comment 2 Answers Sorted by: 2 You're pretty close. A few things should clear it up. First, when you declare parameters with [& varname] that means varname will be a list containing all the extra parameters. bas jasa pelangi